(1+7m)(1-7m)=1-14m^2

Solution for (1+7m)(1-7m)=1-14m^2 equation:

(1+7m)(1-7m)=1-14m^2

We move all terms to the left:

(1+7m)(1-7m)-(1-14m^2)=0

We add all the numbers together, and all the variables

-(1-14m^2)+(7m+1)(-7m+1)=0

We get rid of parentheses

14m^2+(7m+1)(-7m+1)-1=0

We multiply parentheses ..

14m^2+(-49m^2+7m-7m+1)-1=0

We get rid of parentheses

14m^2-49m^2+7m-7m+1-1=0

We add all the numbers together, and all the variables

-35m^2=0

a = -35; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-35)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{-70}=0$